Answer:
Cheryl's age = x = 7 years
Rita's age = y = 17 years
Step-by-step explanation:
Let
Cheryl's age = x
Rita's age = y
Two years ago, Rita was three times older than Cheryl
(y - 2) = 3(x - 2)
y - 2 = 3x - 6
y = 3x - 6 + 2
= 3x - 4
y = 3x - 4
In 3 years, Rita will be twice older than Cheryl
(y + 3) = 2(x + 3)
y + 3 = 2x + 6
y = 2x + 6 - 3
= 2x + 3
y = 2x + 3
Equate both equations
3x - 4 = 2x + 3
Collect like terms
3x - 2x = 3 + 4
x = 7 years
Substitute x = 7 into
y = 2x + 3
= 2(7) + 3
= 14 + 3
= 17
y = 17 years
Cheryl's age = x = 7 years
Rita's age = y = 17 years
Answer:
31.8%
Step-by-step explanation:There are 7 months that have 31 days so,
The odds the first selected month has 31 days is 7/12
The next month there are only 6 months left with 31 days of only 11 months to choose from
so the odds for the second are 6/11
To calculate the odds they BOTH have 31 months you multiply the two odds:
(7/12) x (6/11) = 42/132 = .318 so 31.8%
Umbilical
point.
An
umbilic point, likewise called just an umbilic, is a point on a surface at
which the arch is the same toward any path.
In
the differential geometry of surfaces in three measurements, umbilics or
umbilical focuses are focuses on a surface that are locally round. At such
focuses the ordinary ebbs and flows every which way are equivalent,
consequently, both primary ebbs and flows are equivalent, and each digression
vector is a chief heading. The name "umbilic" originates from the
Latin umbilicus - navel.
<span>Umbilic
focuses for the most part happen as confined focuses in the circular area of
the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces
with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an
outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two
umbilics.</span>
