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3 years ago

What is the area of a rectangle with a base of 7 cm and a height of 11 cm

Mathematics

2 answers:

Advocard [28]3 years ago

7 0

Answer:

77 cm

Step-by-step explanation:

gayaneshka [121]3 years ago

5 0

Answer: 77

Step-by-step explanation:

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4 years ago

Use the digits 1-7 to crest a seven digit number that can be rounded off to 6,300,000

Ne4ueva [31]

6,277,765 rounds up to 6,300,00

7 0

3 years ago

Help plz!

julia-pushkina [17]

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4 0

4 years ago

Which is the prime factorization of 40?

Lana71 [14]

Hey there!

Which is the prime factorization of 40?

Option A.

2 * 5

= 2 + 2 + 2 + 2 + 2

= 4 + 4 + 2

= 8 + 2

= 10

Option B.

2^3 * 5

= 2 * 2 * 2 * 5

= 4 * 2 * 5

= 8 * 5

= 40

Option C.

2 * 53

= 53 * 2

= 53 + 53

= 106

2 * 3 * 5

= 6 * 5

= 6 + 6 + 6 + 6 + 6

= 12 + 12 + 6

= 24 + 6

= 30

Therefore, your answer is:

Option B. 2^3 * 5

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

4 0

2 years ago

WORTH 20 POINTS HELP

vfiekz [6]

Below represents the proof that the quadrilateral QRST is a parallelogram

<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

R = (2,9)

S = (-4,5)

T = (-7,-5)

Calculate the length of each side using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$QR = \sqrt{(-1 - 2)^2 + (-1 -9)^2} = \sqrt{109}$

$RS = \sqrt{(-4 - 2)^2 + (5 - 9)^2} = \sqrt{52}$

$ST = \sqrt{(-7 + 4)^2 + (-5 - 5)^2} = \sqrt{109}$

$TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}$

The above computations show that opposite sides are equal.

Next, we determine the slope of each side using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$QR = \frac{9 + 1}{2 + 3} = \frac{10}3$

$RS = \frac{5-9}{-4 - 2} = \frac{2}3$

$ST = \frac{5+5}{-4 + 7} = \frac{10}3$

$TQ = \frac{-5+1}{-7 + 1} = \frac{2}3$

The above computations show that opposite sides are parallel, because they have equal slope

Hence, the quadrilateral QRST is a parallelogram