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liraira [26]
3 years ago
10

Write the equation of a line that passes through (9,7) and is parallel to y=-4/9+5

Mathematics
1 answer:
bixtya [17]3 years ago
6 0

Answer:

y= -4/9+7

Step-by-step explanation:

if the 2 lines are parallel the slope would be congruent to the other line so y= -4/9+7

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Jobisdone [24]
The area is 36 and the perimeter is 26
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Pleaseee helpppp answer correctly !!!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!
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Answer:

540°

General Formulas and Concepts:

<u>Math</u>

  • Counting

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

  • Sum of Angles: 180(n - 2)°

Step-by-step explanation:

<u>Step 1: Define</u>

We are given a 5-sided polygon (irregular pentagon)

n = 5

<u>Step 2: Find Sum</u>

  1. Substitute in <em>n</em> [Sum of Angles]:                                                                    180(5 - 2)°
  2. (Parenthesis) Subtract:                                                                                   180(3)°
  3. Multiply:                                                                                                           540°
5 0
2 years ago
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Answer please it’s due tomorrow I just need the four in the middle I’m really bad at math...
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Answer:

Number 2: 126

Number 3: 128

Number 4: 75

Number 5: 204

Step-by-step explanation:

7 0
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3 years ago
What is the exact value of cos (67.5°)?
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first off, make sure you have a Unit Circle, if you don't do get one, you'll need it, you can find many online.

let's double up 67.5°, that way we can use the half-angle identity for the cosine of it, so hmmm twice 67.5 is simply 135°, keeping in mind that 135° is really 90° + 45°, and that whilst 135° is on the 2nd Quadrant and its cosine is negative 67.5° is on the 1st Quadrant where cosine is positive, so

cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta) \\\\\\ cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos(135^o)\implies cos(90^o+45^o)\implies cos(90^o)cos(45^o)~~ - ~~sin(90^o)sin(45^o) \\\\\\ \left( 0 \right)\left( \cfrac{\sqrt{2}}{2} \right)~~ - ~~\left( 1\right)\left( \cfrac{\sqrt{2}}{2} \right)\implies -\cfrac{\sqrt{2}}{2} \\\\[-0.35em] ~\dotfill

cos(67.5^o)\implies cos\left( \frac{135^o}{2} \right)\implies \pm \sqrt{\cfrac{ ~~ 1-\frac{\sqrt{2} ~~ }{2}}{2}}\implies \stackrel{I~Quadrant}{+\sqrt{\cfrac{ ~~ 1-\frac{\sqrt{2} ~~ }{2}}{2}}} \\\\\\ \sqrt{\cfrac{ ~~ \frac{2-\sqrt{2}}{2} ~~ }{2}}\implies \sqrt{\cfrac{2-\sqrt{2}}{4}}\implies \cfrac{\sqrt{2-\sqrt{2}}}{\sqrt{4}}\implies \cfrac{\sqrt{2-\sqrt{2}}}{2}

8 0
1 year ago
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