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Sindrei [870]
3 years ago
6

Please help me out!! 24n = 6 n = ?

Mathematics
2 answers:
Travka [436]3 years ago
5 0
Divide 24 from both sides
Phoenix [80]3 years ago
4 0

Answer:

n = 1/4

Step-by-step explanation:

24n = 6

24n = 6

------------

24       24

n = 1/4 or 0.25

Hope this helps

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What is area?
valentinak56 [21]

Answer:

The space inside a circle

Step-by-step explanation:

6 0
3 years ago
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Plot J(-2,8), K(0,8), L(1,0), and M(1,-2) in a coordinate plane. Then determine whether JK and LM are congruent. A. Cannot be de
mr_godi [17]

Answer:

C. JK and LM are congruent

Step-by-step explanation:

Given the coordinates J(-2,8), K(0,8), L(1,0), and M(1,-2), in other to determine whether JK is congruent to LM, we need to determine if the length of side JK and LM are equal i.e JK = LM

To get JK:

We will find the distance between the coordinates J(-2,8), K(0,8) to get the length JK using the formula:

JK =√(x2-x1)²+(y2-y1)²

JK = √(0-(-2))²+(8-8)²

JK = √2²+0²

JK = √4

JK = 2

For the length of LM with coordinate L(1,0), and M(1,-2)

LM = √(1-1)²+(-2-0)²

LM = √0²+(-2)²

LM = √0²+2²

LM = √0+4

LM =√4

LM = 2

Since JK = LM = 2 units, this means that JK and LM are congruent.

7 0
3 years ago
A survey of 1050 eligible voters, an approximate 98% confidence interval estimate for the proportion of voters who claimed to ha
Novosadov [1.4K]

Answer:

There is a 98% confidence that the true proportion of voters who have voted in the last presidential election lies in this interval.

Step-by-step explanation:

The confidence interval for estimating the population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The 98% confidence interval estimate for the proportion of voters who claimed to have voted in the last presidential election was (0.616, 0.681).

The sample taken was of size, <em>n</em> = 1050.

<u>Interpretation</u>:

The 98% confidence interval (0.616, 0.681) for the proportions of voters who claimed to have voted in the last presidential election implies that the true proportion of voters who have voted lies in this interval with 0.98 probability.

Or, there is a 98% confidence that the true proportion of voters who have voted in the last presidential election lies in this interval.

Or, if 100 such samples are taken and 100 such 98% confidence interval are made then 98 of these confidence intervals would consist of the true proportion of voters who have voted in the last presidential election.

8 0
3 years ago
A 4-h club held a canned food drive. On Wednesday they collected 63 cans which was 21% of the total cans collected during the fo
zheka24 [161]
63=21% of all
percent is parts out of 100
63=21/100 of all
times both sides by 100/21
6300/21=all
300=all

all-wednesday=thu+fri
300-63=thu+fri
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4 0
3 years ago
(6m4) (8m2) multiply
aev [14]
6 m^4 * 8 m^2
= 48 m^(4+2)
= 48m^6
4 0
3 years ago
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