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OverLord2011 [107]
2 years ago
15

Please divide and simplify

Mathematics
1 answer:
Damm [24]2 years ago
3 0

Answer:

-2y^{3

Step-by-step explanation:

<h2>{\frac{18x^{3} y^{5} }{9x^{3} y^{2} } \\</h2><h2>Divide the numbers=</h2><h2>\frac{2x^{3} y^{5} }{x^{3} y^{2} }</h2><h2>Apply exponent rule=</h2><h2>2y^{5-2}</h2><h2>Subtract numbers=</h2><h2>-2y^{3</h2><h2 />
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Given: sin ∅= 4/5 and cos x = -5/13 ; evaluate the following expression.<br><br> tan( ∅ - x )
Pavlova-9 [17]

By definition of tangent,

tan(θ - x) = sin(θ - x) / cos(θ - x)

Expand the sine and cosine terms using the angle sum identities,

sin(x ± y) = sin(x) cos(y) ± cos(x) sin(y)

cos(x ± y) = cos(x) cos(y) ∓ sin(x) sin(y)

from which we get

tan(θ - x) = (sin(θ) cos(x) - cos(θ) sin(x)) / (cos(θ) cos(x) + sin(θ) sin(x))

Also recall the Pythagorean identity,

cos²(x) + sin²(x) = 1

from which we have two possible values for each of cos(θ) and sin(x):

cos(θ) = ± √(1 - sin²(θ)) = ± 3/5

sin(x) = ± √(1 - cos²(x)) = ± 12/13

Since there are 2 choices each for cos(θ) and sin(x), we'll have 4 possible values of tan(θ - x) :

• cos(θ) = 3/5, sin(x) = 12/13 :

tan(θ - x) = -56/33

• cos(θ) = -3/5, sin(x) = 12/13 :

tan(θ - x) = 16/63

• cos(θ) = 3/5, sin(x) = -12/13 :

tan(θ - x) = -16/63

• cos(θ) = -3/5, sin(x) = -12/13 :

tan(θ - x) = 56/33

7 0
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Read 2 more answers
Solve for the variable. -2x = -15
MakcuM [25]
The variable is x=15/2
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