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3 years ago

12

For each of the following equations,give the centre and radius of the circle.

1 answer:

allsm [11]3 years ago

5 0

Answer:

a) Center is (0,0) and radius r = 5

b) Center is (0,0) and radius r = 1

d) Center is (5,3) and radius r = 9

e Center is (-2,1) and radius r = 3

g) Center is (-1,-3) and radius r = 7

h) Center is (0,0) and radius r = 2.5

Step-by-step explanation:

<u><em>a)</em></u>

Given circle x² + y² = 25

The standard form of circle equation is

( x-h)² +(y-0)² = r²

Center is (0,0) and radius r = 5

b)

Given circle x² + y² = 1

The standard form of circle equation is

( x-h)² +(y-0)² = r²

Center is (0,0) and radius r = 1

d)

Given circle (x-5)² + (y-3)² = 81

The standard form of circle equation is

( x-h)² +(y-0)² = r²

(x-5)² + (y-3)² = 9²

Center is (5,3) and radius r = 9

e)

Given circle (x+2)² + (y+1)² = 9

The standard form of circle equation is

( x-h)² +(y-0)² = r²

(x+2)² + (y+1)² = 3²

Center is (-2,-1) and radius r = 3

g)

Given circle (x+1)² + (y+3)² = 49

The standard form of circle equation is

( x-h)² +(y-0)² = r²

(x+1)² + (y+3)² = 7²

Center is (-1,-3) and radius r = 7

h)

Given circle x² + y² = 6.25

The standard form of circle equation is

( x-h)² +(y-0)² = r²

Given circle x² + y² = (2.5)²

Center is (0,0) and radius r = 2.5

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The shape of the clock is a regular dodecagon with a radius of 14cm. Centered on the clock's face is a green circle of radius 9c

faust18 [17]

The area of a dodecagon is 1/2aP
where:
a-apothem
P-perimeter

In the figure you will draw a point to any side and make a line perpendicular from a center to that side. Then if u think u can see that with only one draw of a hypotenuse can form a triangle. Then after drawing the hypotenuse which has 2 triangles, make the top angle of 1 triangle there are 30 degrees. On the down part is perpendicular and the left or the right is the 60 degrees. After that using special right triangles like the 30, 60, 90,. Then at the base of the one it bisected dived them by 2 for the 2 triangle's base. After that solve using it since the radius is 14. The apothem is 14(sqrt of 3). So after solving them the perimeter of each dodecagon is 12 sided so 14x12 is 168

A=1/2aP
A=1/2(14)(sqrt of 3)(168)
A=1176(sqrt of 3)

Thats the area of the dodecagon now the circle

A=(pi)r^2
A=(pi)(9)^2
A=81pi

Therefore the color purple is greater than the color green

8 0

3 years ago

I need help figuring this out asap please

Vera_Pavlovna [14]

Answer:

38.13 ft squared

Step-by-step explanation:

Since it is half of a circle we first find the area of a normal circle then divide by two.

So to find the area of a circle it is pi times radius squared which in this case it would be 3.14 times 9 = 28.26

Then since it is a half circle we divide by two so

28.26/2 = 14.13

Then to find the area of the triangle we do 4 times 6 which is 24.

now we add the two which is 14.13 + 24 which is

38.13

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3 years ago

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AVprozaik [17]

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3 years ago

Show that y=cos(t)y=cos(t) is a solution to (dydt)2=1−y2(dydt)2=1−y2. Enter your answers below in terms of the independent varia

GrogVix [38]

Answer:

$(\frac{dy}{dt})^2=sin^2t$

Step-by-step explanation:

$y=cost$

DE : $(\frac{dy}{dt})^2=1-y^2$

If y is a solution of given DE then it satisfied the DE.

Differentiate w.r.t t

$\frac{dy}{dt}=-sint$

Using the formula

$\frac{d(cosx)}{dx}=-sinx$

LHS: $(\frac{dy}{dt})^2=(-sint)^2=sin^2t$

RHS

$1-y^2=1-cos^2t=sin^2t$

By using the formula

$sin^2t=1-cos^2t$

LHS=RHs

Hence, y is a solution of given DE

$(\frac{dy}{dt})^2=sin^2t$

7 0

3 years ago

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valentinak56 [21]

Answer:

Step-by-step explanation:

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3 years ago