No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.
Consider polynomial equations x^2 = 3 and x^2 = 1.
Obviously they have real solutions.
Subtract the two polynomial equations:
(x^2 - x^2) = (3 - 1)
0 = 2...
We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.
Obviously 0 = 2 has no real solution.
Answer:
28
Step-by-step explanation:
In a regular 52 card deck, 26 are black (clubs or spades). Additionally, there are two red jacks (diamonds and hearts). This equals 28/52. As a probability, it would be 28/52=14/26=7/13. This could also be expressed as a percentage or decimal. 0.538 or 53.8%. But the question asks <em>how many ways</em> can she choose a jack or black card, so I’m assuming they don’t want the probability, just the number, which is 28.
The answer is 3 and you get that by using the formula for the area of rectangle, p=2L+2W
44=2(4+5w) + 2w
44=8+10w + 2w
44=8+12w
44-8=8+12w-8
36=12w
36/12=12w/12
3=w
If you plug 3 back into the original formula then you see that it is equal to the perimeter of 44
P=2(4+5w) + 2w
P=2(4+5•3) + 2(3)
P=2(19) +6
P=38+6
P=44
The answer is 3 because the length of the box is 10, the width is 5, and the height is 3.
Answer:
Step-by-step explanation:
<u>Step 1: Convert words into numbers
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<u>Step 2: Multiply
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<u>Step 3: Divide
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Answer:
