All categories

3 years ago

What do I do with the “y = -f(x) +6” given to find the Domain and Range?

Mathematics

2 answers:

Bond [772]3 years ago

7 0

Answer: hvfiikncdnf;oewh;d..ew

Step-by-step explanation:

Kamila [148]3 years ago

5 0

Answer:

Step-by-step explanation:

a.Changing f with -f does not change its domain, it just flips the image across the x axis. Adding 6 to the result, just shifts everything towards the positive y by 6 units. Domains stays the same, from -4 to +8. Range instead goes up, the lowest value is -2+6 = 4 and the highest value is 2+6 = 8.

So domain remains the same [-4; 8] and range goes to [4;8]

a. This time we're shifting everything on the horizontal axis, one unit to the left (the way to remember it is that f(x) has a minimum at x=4, while after the shift the new value happens at x=3) multiplying the value by 3 means that every value gets scaled up. It means the minimum becomes -2*3= -6 and the maximum happens at 2*3= 6. The shift brings the domain to [-5;7] and the range to [-6,6]

You might be interested in

10) Nicole has a 5 lb bag of carrots and a 2 oz bag

maria [59]

Answer:

5 lbs and 2 ozs

Step-by-step explanation:

16 ounces = 1 lbs.

So just add the 2 ounces to the pounds.

5 0

3 years ago

Read 2 more answers

Areas of the circles ?

Orlov [11]

Look at the attached picture⤴

Hope this will help u....

5 0

3 years ago

Find the equation (in standard form) whose center is (5, -3) and goes through (2, 5).

yanalaym [24]

We can write this as

(x - 5)^2 + (y + 3)^2 = r^2

where r = radius

Plugging in the point (2,5) we have

(2-5)^2 + (5+3)^2 = r^2
r^2 = 9 + 64 = 73
so the required equation is

(x - 5)^2 + (y + 3)^2 = 73

3 0

3 years ago

The average of a list of 4 numbers is 90.0. A new list of 4 numbers has the same first 3 numbers as the original list, but the f

Thepotemich [5.8K]

Answer:

the average of this new list of numbers is 94

Step-by-step explanation:

Hello!

To answer this question we will assign a letter to each number for the first list and the second list of numbers, remembering that the last number of the first list is 80 and the last number of the second list is 96

for the first list

$\frac{a+b+c+80}{4} =90$

for the new list

$\frac{a+b+c+96}{4} =X$

To solve this problem consider the following

1.X is the average value of the second list

2. We will assign a Y value to the sum of the numbers a, b, c.

a + b + c = Y to create two new equations

for the first list

$\frac{y+80}{4} =90$

solving for Y

Y=(90)(4)-80=280

Y=280=a+b+c

for the second list

$\frac{y+96}{4} =X\\$

$\frac{280+96}{4} =X\\x=94$

the average of this new list of numbers is 94

4 0

3 years ago

Read 2 more answers

Arithmetic Sequences:

lisov135 [29]

Início = 6 h
9 x 6 = 54
6:54 passou o nono ônibus
próximo ônibus = 6:54 + 9 = 7:03
próximo = 7:03 + 9 = 7:12
próximo = 7:12 + 9 = 7:21
você chegou às 7:16 e vai esperar 21-16 = 5 minutos

3 0

3 years ago