The product of 5 is better than 20
Answer:
Step-by-step explanation:
The answer for x is 150
Answer:
a) Attached
b) P=0.60
c) P=0.80
d) The expected flight time is E(t)=122.5
Step-by-step explanation:
The distribution is uniform between 1 hour and 50 minutes (110 min) and 135 min.
The height of the probability function will be:
Then the probability distribution can be defined as:
![f(t)=\frac{1}{25}=0.04 \,\,\,\,\\\\t\in[110,135]](https://tex.z-dn.net/?f=f%28t%29%3D%5Cfrac%7B1%7D%7B25%7D%3D0.04%20%5C%2C%5C%2C%5C%2C%5C%2C%5C%5C%5C%5Ct%5Cin%5B110%2C135%5D)
b) No more than 5 minutes late means the flight time is 125 or less.
The probability of having a flight time of 125 or less is P=0.60:
c) More than 10 minutes late means 130 minutes or more
The probability of having a flight time of 130 or more is P=0.80:
d) The expected flight time is E(t)=122.5
That would be -20. a negative divided by a negative number is positive, positive divided by negative is negative bc even numbers of negatives make it positive. and ofc 20 x 5 = 100, hence the ‘20’
<span> (x + 3) • (x - 12)
</span>
The first term is, <span> <span>x2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> -9x </span> its coefficient is <span> -9 </span>.
The last term, "the constant", is <span> -36 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -36 = -36</span>
Step-2 : Find two factors of -36 whose sum equals the coefficient of the middle term, which is <span> -9 </span>.
<span><span> -36 + 1 = -35</span><span> -18 + 2 = -16</span><span> -12 + 3 = -9 That's it</span></span>
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -12 and 3
<span>x2 - 12x</span> + 3x - 36
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-12)
Add up the last 2 terms, pulling out common factors :
3 • (x-12)
Step-5 : Add up the four terms of step 4 :
(x+3) • (x-12)
Which is the desired factorization
Final result :<span> (x + 3) • (x - 12)</span>
