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pickupchik [31]
3 years ago
5

Estimate the value of √2

Mathematics
2 answers:
Simora [160]3 years ago
4 0
You’re answer would be B 0.50
marusya05 [52]3 years ago
3 0

Answer:

B. 0.50

Step-by-step explanation:

It claims to estimate. Square root of 2 would be somewhere around 1. Square root of 5 would be somewhere around 2. Then you divide, 1/2, and that should equal 0.50.

I hope this is correct!

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Do the ratios 1/2 and 6/12 form a proportion
lawyer [7]

Answer:

Step-by-step explanation:

Yes because 6 is 1/2 of 12

6 0
3 years ago
Read 2 more answers
Write the domain as an inequality​
Pavlova-9 [17]

Answer:

x\leq 0

Step-by-step explanation:

The domain is the span of x-values covered by the graph.

From the graph, we can see that the x-values covered by the graph is all values to the left of zero including zero.

Therefore, the domain is all x-values less than or equal to 0:

x\leq 0

Further notes:

In interval notation, this is:

(-\infty,0]

4 0
3 years ago
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If the reciprocal of the number $X$ equals $\frac{2}{7}$, what is $5$ divided by $X$?
grigory [225]
U can find the reciprocal of a number by flipping the number.
example : the reciprocal of 1/5 is 5/1....the reciprocal of 2/3 = 3/2.

the reciprocal of x = 2/7.....that means x = 7/2

5 / (7/2) = when dividing fractions, flip what u r dividing by, then  multiply
5 * 2/7 =
10/7 or 1 3/7 <==
5 0
3 years ago
Jeff has $6000 in a savings account, has $15000 in investments, he owned a guitar worth $1000, he has $17000 left to pay on his
Law Incorporation [45]

Answer:

$200

Step-by-step explanation:

To find Jeff's net worth, we will deduct all his debts (liabilities) from his assets (his properties).

ASSETS

Savings Account - $6000

Investments - $15000

Guitar - $1000

TOTAL - $22000

LIABILITIES

Student loans - $17000

Credit Card Debt - $1200

Outstanding car payment - $3600

TOTAL - $21800

NET WORTH = Assets - Liabilities

NW = $22000 - $21800

NW = $200

His net worth is $200.

4 0
3 years ago
How do you determine if a relation is quadratic by calculation differences, analyzing a graph, examining the degree in an equati
Kryger [21]

1) We can determine by the table of values whether a function is a quadratic one by considering this example:

x | y 1st difference 2nd difference

0 0 3 -0 = 3 7-3 = 4

1 3 10 -3 = 7 11 -7 = 4

2 10 21 -10 =11 15 -11 = 4

3 21 36-21 = 15 19-5 = 4

4 36 55-36= 19

5 55

2) Let's subtract the values of y this way:

3 -0 = 3

10 -3 = 7

21 -10 = 11

36 -21 = 15

55 -36 = 19

Now let's subtract the differences we've just found:

7 -3 = 4

11-7 = 4

15-11 = 4

19-15 = 4

So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.

3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2

4 0
1 year ago
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