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3 years ago

Francesca must buy over $55 worth of art supplies to qualify for free shipping

Mathematics

1 answer:

sattari [20]3 years ago

3 0

Answer

the question isn't complete

Step-by-step explanation

cool

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4. Polynomial Division<br> Divide. (x3 – 2x – 3) ÷ (x + 3)

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3 years ago

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3 years ago

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Alex_Xolod [135]

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Step-by-step explanation:

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3 years ago

An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining.

Tanya [424]

Answer:

98% Confidencce Interval is ( 3030.6, 7467.4 )

Step-by-step explanation:

Given that:

Sample size $n_1 =$ 71

Sample size $n_2 =$ 31

Sample mean $\overline x_1 =$ 41628

Sample mean $x_2 =$ 36,379

Population standard deviation $\sigma_1$ = 4934

Population standard deviation $\sigma_2 =$ 4180

At 98% confidence interval level, the level of significcance = 1 - 0.98 = 0.02

Critical value at $z_{0.02/2} = 2.33$

The Margin of Error = $z \times \sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2} }$

= $2.33 \times \sqrt{\dfrac{4934^2}{71}+\dfrac{4180^2}{31} }$

= $2.33 \times \sqrt{\dfrac{24344356}{71}+\dfrac{17472400}{31} }$

= $2.33 \times \sqrt{906504.06 }$

= 2218.40

The Lower limit = $( \overline x_1 - \overline x_2) - (Margin \ of \ error)$

= ( 41628 - 36379 ) - ( 2218.40)

= 5249 - 2218.40

= 3030.6

The upper limit = $( \overline x_1 - \overline x_2) + (Margin \ of \ error)$

= ( 41628 - 36379 ) + ( 2218.40)

= 5249 + 2218.40

= 7467.4

∴ 98% Confidencce Interval is ( 3030.6, 7467.4 )

5 0

3 years ago

A total of $6000 is invested: part at 5% and the remainder at 9%. How much is invested at each rate if the annual interest is $5

notsponge [240]

Account 1 = $5750 Interest 9% = $517.50
Account 2= $ 250 Interest 5% = $ 12.50

$517.50+$12.50=$350

7 0

3 years ago