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Lady bird [3.3K]
3 years ago
12

Can someone help me pls

Mathematics
1 answer:
NikAS [45]3 years ago
8 0

Answer:

Step-by-step explanation:

what do you want me to do???

just tell me what to do

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The pitcher paid $70.

The second baseman paid $63.

$70 -$63 = $7

Step-by-step explanation:

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please help! A cheetah travels at a rate of 90 feet per second.The distance d traveled by the cheetah is a function of seconds t
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What is the force of a baseball that has a mass of 10 kg and has an acceleration of 30 m/s squared?
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3 years ago
Suppose a movie starts at 5:00 p.m. and Lindsay, a customer who is always late, arrives at the movie theater at a random time be
Arte-miy333 [17]

Answer:

a) We know that the distribution for X is given by: X \sim Unif (a=10, b=45)

The density function for this distirbution is given by:

f(x) = \frac{1}{b-a}= \frac{1}{45-10}= \frac{1}{35} , 10 \leq X \leq 45

So then the height of the uniform density curve would be given by:

h = \frac{1}{35}= 0.029

b) For this case we want to calculate the following probability:

P(X\leq 20)

And we can use the cumulative distribution function given by:

F(X) =\frac{x-a}{b-a}=\frac{x-10}{35} , 10 \leq X \leq 45

And we can calculate the probability like this:

P(X \leq 20) = F(20) = \frac{20-10}{35}=0.286

Step-by-step explanation:

For this case we define our random variable X="Lindsay's late arrival time, in minutes"

Part a

We know that the distribution for X is given by: X \sim Unif (a=10, b=45)

The density function for this distirbution is given by:

f(x) = \frac{1}{b-a}= \frac{1}{45-10}= \frac{1}{35} , 10 \leq X \leq 45

So then the height of the uniform density curve would be given by:

h = \frac{1}{35}= 0.029

Part b

For this case we want to calculate the following probability:

P(X\leq 20)

And we can use the cumulative distribution function given by:

F(X) =\frac{x-a}{b-a}=\frac{x-10}{35} , 10 \leq X \leq 45

And we can calculate the probability like this:

P(X \leq 20) = F(20) = \frac{20-10}{35}=0.286

7 0
4 years ago
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