Answer:
Probability that the proportion of airborne viruses in a sample of 529 viruses would be greater than 8% is 0.9545.
Step-by-step explanation:
For the given population the distribution of air-borne viruses is given as 6%. Now for this the value of Z score is given as
Here
is the sample measure which is 8% or 0.08- p is the population measure which is 6% or 0.06
- n is the number of samples which is 529
So the Z score is given as
For this the score, the value of probability is calculated from the table as below:
Here value of p(Z<-1.6955) is given as 0.0455
Answer:
Since, we are given table for x and y values
and table for average rate of changes
we can see the pattern of average rate of change
average rate of change for 5 to 6 is three times average rate of change for 4 to 5
but we have to find
average rate of change for 7 to 8
so, using same pattern
average rate of change for 6 to 7 is three times average rate of change for 5 to 6
average rate of change for 7 to 8 is 3*3( average rate of change for 5 to 6)
so, we can plug value
average rate of change for 7 to 8 is 3*3*486
average rate of change for 7 to 8 is 4374
so, option-D...........Answer
Step-by-step explanation:
Answer:
the answer is c
Step-by-step explanation:
Answer:
Just Multiply them together
Step-by-step explanation:
