This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x).
<span>Multiplying both sides of the equation by the integrating factor: </span>
<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>
<span>The left side is the derivative of ye^(6x), hence </span>
<span>d/dx[ye^(6x)] = e^(12x) </span>
<span>Integrating </span>
<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>
<span>y = (1/12)e^(6x) + ce^(-6x) </span>
<span>Use the initial condition y(0)=-8 to find c: </span>
<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>
<span>Hence </span>
<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
Answer:
Step-by-step explanation:
Given that g is a function from g : {1, 2, 3} ->{1, 2, 4, 8}
by the function

i.e. we have 
Range = {2,4,8} Since there is an extra element 1 in the co domain which is not in range , g is not on to
But g is one to one as 1,2,3 have different images.
9514 1404 393
Answer:
y = -(x+1)^2 +3
Step-by-step explanation:
Translating f(x) left by 1 unit replaces x with x+1.
Translating f(x) up by 3 units replaces f(x) with f(x)+3.
Reflecting f(x) over the x-axis replaces f(x) with -f(x).
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When y = x^2 is reflected over the x-axis, it becomes ...
y = -x^2
When y = -x^2 is translated 1 unit left, it becomes ...
y = -(x +1)^2
When y = -(x+1)^2 is translated 3 units up, it becomes ...
y = -(x +1)^2 +3
Work shown above! Box a is 240 lbs Box b is 120 and Box c is 150 lbs hope this helps c: