The first answer is correct, if you go back by 5% each year you will see that.
<span>The term that you want is 5C2*p^2*q^3
representing 2 successes and 3 failures. This term's value is</span>
<span>(5C2)(0.5^5)
= 10*0.03125 = 0.3125 = P(2 successes in 5 trials) =31.3% </span>
Answer:
sorry
Step-by-step explanation:
Yes, because 54 is divisible by 3
I would really really appreciate it if you marked me as brainliest ☆〜（ゝ。∂）
