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3 years ago

14

One fifth of the animals at the shelter are stray cats. If there are 13 stray cats at the shelter, how many animals are there in

total?

1 answer:

Natali [406]3 years ago

4 0

Answer:

1/5 x X = 13

x5 x5

x = 65 in total

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Find the exact values of the remaining five trigonometric functions of o satisfying the given conditions.

Lyrx [107]

First, tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>), so if cos(<em>θ</em>) = 3/5 > 0 and tan(<em>θ</em>) < 0, then it follows that sin(<em>θ</em>) < 0.

Recall the Pythagorean identity:

sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1

Then

sin(<em>θ</em>) = -√(1 - cos²(<em>θ</em>)) = -4/5

and so

tan(<em>θ</em>) = (-4/5) / (3/5) = -4/3

The remaining trig ratios are just reciprocals of the ones found already:

sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/3

csc(<em>θ</em>) = 1/sin(<em>θ</em>) = -5/4

cot(<em>θ</em>) = 1/tan(<em>θ</em>) = -3/4

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3 years ago

The Art and History Museum offers a family discount card for a donation of $57. I The table shows the price per person with and

Murljashka [212]

Answer:

8 number of visits will be the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

Step-by-step explanation:

Price without Discount Card Price with Discount Card

Ticket (12 & Under) $10 $8

Adult's Ticket $15 $12

Let x be the number of visits

Price without discount card for 2 adults and 1 child ticket

Price without discount for x visits = $x(15 \times 2+ 10)=40x$

Price with discount for x visits = $57+ x(12 \times 2+ 8)=57+32x$

Now to find For what number of visits will the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

57+32x< 40x

57<8x

7.1<x

So, 8 number of visits will be the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

8 0

3 years ago

144=12x <br> 45 =4x-27 <br> 2x-2=14 <br> 12x=44-10x does any one kno these questions?

Free_Kalibri [48]

Hello russell6333!

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve for x.

144 = 12x
45 = 4x - 27
2x - 2 = 14
12x = 44 - 10x

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$1) \: \: \: 144 = 12x \\ \frac{144}{12} = x \\ \boxed{ \boxed{ \bf12 = x}}$

__________________

$2) \: \: \: 45 = 4x - 27 \\ 45 + 27 = 4x \\ 72 = 4x \\ \frac{72}{4} = x \\ \boxed{ \boxed { \bf18 = x }}$

__________________

$3) \: \: \: 2x - 2 = 14 \\ 2x = 14 - 2 \\ 2x = 12 \\ x = \frac{12}{2} \\ \boxed{ \boxed{ \bf \: x = 6}}$

__________________

$4) \: \: \: 12x = 44 - 10x \\ 12x + 10x = 44 \\ 22x = 44 \\ x = \frac{44}{22} \\ \boxed{\boxed{ \bf \: x = 2}}$

__________________

<h3><u>NOTE </u><u>:</u><u>-</u></h3>

To solve questions of these sorts, bring all the terms to one side & simplify it leaving x alone in the other side of the equation (other side of the equal to sign). After simplification you'll get the value of x.
Remember that the signs & operations will change when you bring a term to the other side of the equation.
So, addition will become subtraction, subtraction will become addition, multiplication will become division & division will become multiplication.

__________________

Hope it'll help you!

ℓu¢αzz ッ

8 0

3 years ago

Read 2 more answers

Solve for k, 6k-2z=12

Alenkinab [10]

The previous question I answered was exactly like this.

6(4) - 2(6) = 12.

K = 4.

4 0

3 years ago

What is the surface area of the solid shown below?

Ugo [173]

Answer:

$\text{C. }156\:\mathrm{cm^3}$

Step-by-step explanation:

The surface area of the triangular prism consists of three rectangles and two triangles.

Rectangle One - 5 x 12 = 60 cm^2

Rectangle Two - 4 x 12 = 48 cm^2

Rectangle Three - 3 x 12 = 36 cm^2

Triangles - 2 x 1/2 x 3 x 4 = 12 cm^2

Thus, the total surface area of the solid is $60+48+36+12=\boxed{\text{C. }156\:\mathrm{cm^3}}$

8 0

3 years ago