Answer:
x=3.9 or 39/10 and y=3.13333 or 47/15
Step-by-step explanation:
Since both expressions (6x-3y) and (3-2x+6y) are equal to 14, separate the equations:
6x-3y=14 and 3-2x+6y=14
Simplify the equations
6x-3y=14 and -2x+6y=11
Now, line the equations up and pick a variable (either x or y) to eliminate
6x-3y=14
-2x+6y=11
In this case, let's eliminate y first. To do so make the y values in both equations the same but with opposite signs. Make both be 6y but one is +6y and the other -6y
Multiply (6x-3y=14) by 2 to get:
12x-6y=28
Line the equations up and add or subtract the terms accordingly
12x-6y=28
-2x+6y=11
This becomes:
10x+0y=39
Isolate for x
x= 39/10 or x= 3.9
Now substitute the x value into either of the original equations
6x-3y=14
6(3.9)- 3y=14
Isolate for y
23.4-14=3y
3y= 9.4
y= 3.1333 (repeating) or y= 47/15
Answer:
Step-by-step explanation:
Step 1: rewrite the equation of the given line in to slope-intercept form by solving for y
3y + 5x = 6
3y = -5x + 6 (subtract 5x from both sides)
y = -(5/3)x + 2 (divide both sides by 3)
Step 2: Our line is parallel to this line, so it has the same slope, and a
y-intercept of 4, so we have...
y = -(5/3)x + 4
*slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept,
Answer:
11 17/24
Step-by-step explanation:
To find this out we have to first find out the least common denominator for 8 and 3 which would be 24, now we have to switch both denominators to 24 but also have to switch the numerators to how much we multiplied the denomintors by and then add. so we multiplied 8 by 3 to get it to 24 so we multiply the numerator 3 by 3 as well. and for the second fraction we multiply the denominator 3 by 8 to get 24 so we multiply the nuerator by 8 as well. so...
6 3/8+ 5 1/3= 6 9/24 + 5 8/24 = 11 17/24
Answer:
(1, 3)
Step-by-step explanation:
Solve the following system:
{y - x = 2 | (equation 1)
{x + y = 4 | (equation 2)
Add equation 1 to equation 2:
{-x + y = 2 | (equation 1)
{0 x+2 y = 6 | (equation 2)
Divide equation 2 by 2:
{-x + y = 2 | (equation 1)
{0 x+y = 3 | (equation 2)
Subtract equation 2 from equation 1:
{-x+0 y = -1 | (equation 1)
{0 x+y = 3 | (equation 2)
Multiply equation 1 by -1:
{x+0 y = 1 | (equation 1)
{0 x+y = 3 | (equation 2)
Collect results:
Answer: x = 1, y = 3
A!!
-2 and 2 are the x values of the coordinates which are 4 units apart, being 4 units in LENGTH
1 and -2 are 3 units apart and them being in the y part of the coordinate it’s 3 units wide
