Question

Consider the reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O. In an acid-base tritration, the stoichiometric point happens when 43.44 mL of 0.2753 M NaOH is added to a 54.69 mL portion of H2SO4. What is the molar concentration of H2SO4 expressed in M?

Answer 1

            moles NaOH = c · V = 0.2753 mmol/mL · 43.44 mL = 11.959032 mmol
            moles H2SO4 = 11.959032 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 5.979516 mmol
Hence
            [H2SO4]= n/V = 5.979516 mmol / 54.69 mL = 0.1093 M
The answer to this question is  [H2SO4] = 0.1093 M