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svetlana [45]
3 years ago
7

Which shows the general structure of a carboxylic acid

Chemistry
1 answer:
taurus [48]3 years ago
3 0

Answer:b

Explanation:

I just did it

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Coefficient -<br> 2) V205<br> Subscript for V<br> Subscript for 0 -<br> HELPPP
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there are 2 V's and there are 5 O's

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3 years ago
a steel cylinder is left out in the sun the pressure at 2:00 pm was 1014 kpa at 33.0 c at 7:00 am at a temperature of 21.4c what
e-lub [12.9K]
The easiest way is to use the Law of Gay-Lussac. This law states that there is a direct relation between the temperature in Kelvin of a gas and the pressure.

Then, namig p the pressure and T the temperature in Kelvin and using subscripts for every state:

p/T is constant ==> p_1 / T_1 = p_2/T_2

From which you obtain:

p_2 = [p_1 / T_1] * T_2

T_1 = 33.0 + 273.15 = 306.15 K
T _2 = 21.4 + 273.15 = 294.55 K

p_1 = 1014 kPa

p_2 = 1014 kPa * 294.55 K / 306.15 K = 975.6 kPa
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Alex73 [517]

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3 years ago
HELPPP<br>yall please help my sister won't help me ​
ira [324]

\text{H}_3\text{PO}_4  + 3\text{KOH}  \longrightarrow \text{K}_3 \text{PO}_4     +3\text{H}_2 \text{O}\\\\10\text{Na} +2 \text{NaNO}_3  \longrightarrow 6\text{Na}_2 \text{O} + \text{N}_2\\\\\  2\text{H}_3 \text{PO}_4 + 3\text{Mg(OH)}_2 \longrightarrow \text{Mg}_3(\text{PO}_4)_2+6\text{H}_2 \text{O}\\\\2\text{Al(OH)}_3 + 3\text{H}_2 \text{CO}_3 \longrightarrow \text{Al}_2(\text{CO}_3)_3 + 6\text{H}_2 \text{O} \\\\2\text{C}_6\text{H}_6+15\text{O}_2 \longrightarrow 12\text{CO}_2 +6\text{H}_2 \text{O}\\

\text{Pb(OH)}_2 +2\text{HCl} \longrightarrow \text{PbCl}_2 +2 \text{H}_2 \text{O}

2\text{Mn} + 6\text{HI} \longrightarrow 3 \text{H}_2+2\text{MnI}_3

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3 years ago
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