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GarryVolchara [31]
3 years ago
9

What is the circumference of a circle with a diameter of 5 feet? Use 3.14 for pie.

Mathematics
1 answer:
sammy [17]3 years ago
8 0

Answer:

A. 15.7 ft

Step-by-step explanation:

circumference = 2πr

radius= half the diameter 5/2=2.5

2(3.14)(2.5)=15.7 ft

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Answer: \frac{\sqrt{6}-\sqrt{2}}{2}

Step-by-step explanation:

We apply the formula \cos(x+y)=\cos(x)\cos(y)-\sin(x)\sin(y).

Note that  \cos(\frac{41}{12}\pi)=\cos((\frac{36}{12}+\frac{7}{12})\pi)=\cos(3\pi + \frac{7}{12})\pi). Take  x=3\pi and y=\frac{7}{12}\pi in the formula above to get

\cos(\frac{41}{12}\pi)=\cos(3\pi)\cos(\frac{7}{12}\pi)-\sin(3\pi)\sin(\frac{7}{12}\pi)=(-1)\cdot \cos(\frac{7}{12}\pi)-0\cdot\sin(\frac{7}{12}\pi)=-\cos(\frac{7}{12}\pi)

Then the value of this expression is -\cos(\frac{7}{12}\pi)

We can use the cosine addition formula again to simplify further. Decompose the fraction in the argument as:

\cos(\frac{7}{12}\pi)=\cos((\frac{3}{12}+\frac{4}{12})\pi)=\cos((\frac{1}{4}\pi + \frac{1}{3})\pi)

Applying the formula with x=\frac{1}{4}\pi and y=\frac{1}{3}\pi we obtain

\cos(\frac{7}{12}\pi)=\cos(\frac{1}{4}\pi)\cos(\frac{1}{3}\pi)-\sin(\frac{1}{4}\pi)\sin(\frac{1}{3}\pi)=\frac{\sqrt{2}}{2}\cdot\frac{1}{2} -\frac{\sqrt{2}}{2}\cdot\frac{\sqrt{3}}{2}=\frac{\sqrt{2}-\sqrt{6}}{2}

We conclude that this expression has the value -\frac{\sqrt{2}-\sqrt{6}}{2}=\frac{\sqrt{6}-\sqrt{2}}{2}

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