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Lerok [7]
2 years ago
14

(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounde

d to the nearest tenth?
5.7 units


6.3 units


1 unit


4 units
Mathematics
1 answer:
monitta2 years ago
8 0

Using the distance formula, d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\, what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?

Using the points given, plug them into the equation.

d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\d = \sqrt{((4) - (-2))^2 + ((4) - (2)^2  } \\d=\sqrt{(4+2)^2 + (4-2)^2}\\d=\sqrt{(6)^2 + (2)^2}  \\d=\sqrt{36+4} \\d=\sqrt{40} \\

Plug this into a calculator and you get 6.32455532

Since you only need it up to the tenth (0.1), round up 6.32

<em>Five or more, let it soar. Four or less, let it rest.</em>

Since two is lower than four, we drop it.

Therefore, the distance between points (-2, 2) and (4, 4) is 6.3

Hope this helps ^w^

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