Answer:363
Step-by-step explanation:
We have to find partial sum for the sequence 243 , 81 , 27 ..... up to 5 terms(S5 given)
The sequence actually is 3^5,3^4.,3^3.....
Therefore first 5 terms are 1) 3^5 I.e. 243
2) 3^4 I.e. 81
3) 3^3 I.e. 27
4)) 3^2 I.e. 9
5) 3^1 I.e. 3
Adding all those no. we get partial sum of first 5 no. of the sequence
So, 243 + 81 + 27 + 9 + 3
= 363
Hope it helps!!!
Answer:
Step-by-step explanation:
3 consecutive integers....
1st integer = x
2nd integer = x + 1
3rd integer = x + 2
the product of 1st and 3rd is 5 greater then 5 times the 2nd...
x(x+2) = 5(x + 1) + 5
x^2 + 2x = 5x + 5 + 5
x^2 + 2x = 5x + 10
x^2 + 2x - 5x - 10 = 0
x^2 - 3x - 10 = 0
(x - 5)(x + 2) = 0
x - 5 = 0 x + 2 = 0
x = 5 x = -2
so it will be : 5,6,and 7 or -2,-1, and 0
Answer:
the solution is given by s=9 because it makes the value of 3s+12 equal to 21
Step-by-step explanation:
Answer:
the solutions are these
Step-by-step explanation:
Answer:
Step-by-step explanation:
The equations given are:
For the equations to generate the same independent value, then
This implies that:
Group similar terms to get:
Simplify to get:
