Answer:
a) ![[-0.134,0.034]](https://tex.z-dn.net/?f=%5B-0.134%2C0.034%5D)
b) We are uncertain
c) It will change significantly
Step-by-step explanation:
a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.
Since we assume that the variances are equal, we use the pooled variance given as
,
where
.
The mean difference
.
The confidence interval is

![= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]](https://tex.z-dn.net/?f=%3D%20-0.05%5Cpm%201.995%20%5Ctimes%200.042%20%3D%20-0.05%20%5Cpm%200.084%20%3D%20%5B-0.134%2C0.034%5D)
b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.
c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.
Answer:
hmmm cant tell if this is a serious question Lol considering you seem pretty smart but if so answer is 23
Step-by-step explanation:
Answer:
x^2+y^2-32x+24y+375=0
Step-by-step explanation:
Equation of circle with given centre (h,k) and radius=r is
(x-h)^2+(y-k)^2=r^2
Given centre are=(16, - 12) and radius= 5
So equation of circle=
(x-16)^2+(y- -12)^2=5^2
x^2-32x+256+y^2+24y+144=25
x^2+y^2-32x+24y+375=0
Answer
Answer:

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