Answer: We are 95% confident that the mean SPF level of sunscreen used by all Cal Poly students is between 29.0813 and 40.0187.
Step-by-step explanation:
Given : Significance level : 
Sample size : n= 52 , which is a large sample (n>30), so we use z-test.
By using z-value table,
Critical value: 
Sample mean : 
Standard deviation : 
The confidence interval for population means is given by :-

i.e. 

Now, the 95% confidence interval for the ppopulation mean = . (29.0813, 40.0187)
Hence, We are 95% confident that the mean SPF level of sunscreen used by all Cal Poly students is between 29.0813 and 40.0187.
Answer:
Step-by-step explanation:7 ÷4= 4 + 3 ÷ 4 = 30 ÷4 = 2.85
Answer:
The answers are
EBF and FBC
ABD and DBE
Step-by-step explanation:
Let's solve your equation step-by-step.
9x=10
Step 1: Divide both sides by 9.
9x / 9 = 10 /9
x = 10 / 9
Answer:
x = 10 / 9

so, is just that product, recall to use "<span>3.1416 as the value of π".</span>