Answer:
27) x = 2^(y) – 5.
Asymptote: x = -5.
D: x > -5; (-5, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → -infinity.
x → +infinity, f(x) → +infinity.
________________________
28) x = 2^-(y–3).
Asymptote: x = 0.
D: x > 0; (0, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → +infinity.
x → +infinity, f(x) → -infinity.
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29) x = 4^(y–2) + 1.
Asymptote: x = 1.
D: x > 1; (1, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → -infinity.
x → +infinity, f(x) → +infinity.
________________________
Answer:
i'm not one hundred percent but i think it is c
Step-by-step explanation:
Answer:
147.92
Step-by-step explanation:
Let the monthly salary be x
He saves 12 % and that is 17.75
x* 12% = 17.75
Change to decimal form
x *.12 = 17.17
Divide each side by .12
x*.12 /.12 = 17.75/.12
x =147.91666666
Rounding to the nearest cent
x = 147.92
Take a look at the attachment below. It proves that the inverse of matrix P does exists, as <u><em>option c,</em></u>
<u><em /></u>
Hope that helps!
Methods for solving a system of equations:
- elimination
- substitution
- augmented matrix
Ranks of method ( number one being the most preferred method)
1) elimination
2) substitution
3) augmented matrix
Elimination is my preferred method because it is simple and easy to work out and hard to get wrong.
Augmented matrix is my least preferred method because it is easy to get wrong and it requires complex steps to solve a simple equation.
Hope this helps ;)