5 treats divided by six groups of one dog, or in easier terms, five dog treats divided up for 6 dogs. As a fraction, just remove the words except for 5, divided by, and 6, to give you 5/6. Hope this helped.
X = (2^2)^(2.5)
<span>x = 2^(2 * 2.5) </span>
<span>x = 2^5 </span>
<span>x = 32
</span>y^(-3/2) = 125
<span>y^(-3) = 125^2 </span>
<span>y^(-3) = (5^3)^2 </span>
<span>y^(-3) = (5^2)^3 </span>
<span>y^(-3) = 25^3 </span>
<span>y = 25^(-1) </span>
<span>y = 1/25 </span>
<span>x/y => </span>
<span>32 / (1/25) => </span>
<span>32 * 25 => </span>
<span>800 is the simplest form of above
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X-int:let y=0
3x-2(0)=18
3x=18
divide both sides by 3
therefore x=6
y-int:let x=0
3(0)-2y=18
-2y=18
we divide both side by -2
therefore y=-9
The rule of distributive property allows you to rewrite xa + xb as x (a + b).
So if x = 2, a = 3 and b = 4, xa + xb = x(a + b)
(2 * 3) + (2 * 4) = 2 (3 + 4)
6 + 8 = 14
14 = 14
...and so on. You may try it yourself with different variations.
Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.
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