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zysi [14]
3 years ago
14

What is the slope of the line passing through the points (2, – 5) and (4, 1)?

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

B

Step-by-step explanation:

ΔY/ΔX

-5 - 1 / 2 - 4

-6 / -2

3

hope it helps

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A Unites States naval submarine began at sea level. It submerged 140 ft and then traveled 40 miles. It dove down an additional 1
kodGreya [7K]

Answer: -231 ft

<u>Step-by-step explanation:</u>

The submarine started at sea level = 0

It submerged 140 ft = -140 ft

It traveled 40 miles horizontally so it is still at -140 ft

It dove down an additional 120 ft = -260 ft <em>(-140 + -120)</em>

It traveled 25 miles horizontally so it is still at -260 ft

It rose 29 ft = -231 ft <em>(-260 + 29)</em>

Note: submerged and dove are negative values and rose is positive

0 - 140 - 120 + 29 = -231

3 0
3 years ago
Read 2 more answers
Pls awnser this I need it
Lisa [10]

Answer:

-2k + 6

hope its right

-2k - (-5) + 1                    

You should always switch the signs to their opposites if you're mutiplying a negative such as the - (-5)     Hope I make sense

-2k + 5 + 1

-2k + 6

4 0
2 years ago
What is the slope of the line x + 6y= 12
Lubov Fominskaja [6]

x + 6y = 12

You want the y-value to be on one side of the equation, so you have to subtract the x-value from both sides.

6y = -x + 12

Next, you divide both sides by 6, so that the y-value will be by itself.

y = - \frac{1}{6} + 2

We know that the slope or the 'm' value is located before the x-value based on y = mx +b, therefore the slope is - \frac{1}{6}

5 0
3 years ago
Find the expansion of cos x about the point x=0
ycow [4]

Answer:

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

Step-by-step explanation:

We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \frac{f''''(a)(x-a)^4}{4!} + ...

Putting a = 0 and all the values from above in the expansion, we get,

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

8 0
3 years ago
For a standard normal distribution, which of the following expressions must always be equal to 1?
frosja888 [35]
For a standard normal distribution, the expression that is always equal to 1 is P(z≤-a)+P(-a≤z≤a)+P(Z≥a). This expression represents all of the possible values in a curve, or in other words, the total area of a curve. According to standard normal distribution, the total area of a curve is always equal to 1.


8 0
3 years ago
Read 2 more answers
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