3 years ago

In ΔGHI, the measure of ∠I=90°, the measure of ∠G=62°, and GH = 96 feet. Find the length of IG to the nearest tenth of a foot.

Mathematics

2 answers:

Crank3 years ago

8 0

Answer: 45.1feet

Step-by-step explanation:

alexandr402 [8]3 years ago

6 0

Answer:

45.1feet

Step-by-step explanation:

Given the following

∠I=90°

∠G=62°, and

GH = 96 feet = Hypotenuse

Required

IG = Adjacent side

Using the SOH CAH TOA identity

Cos theta = Adj/hyp

Cos 62 =IG/96

IG = 96cos62

IG = 96(0.4695)

IG = 45.1feet

Hence the length of IG to the nearest tenth is 45.1feet

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