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3 years ago

3-2*9^3/-2 Frisk with a Mohawk and muffet with a buzz cut

Mathematics

2 answers:

True [87]3 years ago

7 0

Answer:

That looks awesome!

Step-by-step explanation:

Ugo [173]3 years ago

6 0

Answer:

next up muffet mohawk frisk chelcy and undyne buzz cut

Step-by-step explanation:

and after that undyne gets a mohawlk

You might be interested in

Victoria and Georgetown are 67.2 miles from each other. How far apart would the cities be on a map that has a scale of 0.9 inche

Artemon [7]

Answer: 5.76 miles

Step-by-step explanation:

Let the distance between Victoria and Georgetown on the map be represented by x.

The information given in the question can then be formed into an expression which will be:

0.9/x = 10.5/67.2

Cross multiply

(10.5 × x) = 67.2 × 0.9

10.5x = 60.48

x = 60.48/10.5

x = 5.76

The answer is 5.76 miles

7 0

3 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$

= 1 - 18x + 135x² - 540x³ + 1215 $x^{4}$ - 1458 $x^{5}$ + 729 $x^{6}$

----------------------------------------------------------------------------------

Collecting like terms from both expressions

$(1+3x)^{6}$ + $(1-3x)^{6}$

= 2 + 270x² + 2430 $x^{4}$ + 1458 $x^{6}$

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1 5 10 10 5 1

Decreasing powers of 1 from $1^{5}$ to $1^{0}$

Increasing powers of 2x from $(2x)^{0}$ to $(2x)^{5}$

$(1+2x)^{5}$

= 1. $1^{5}$ $(2x)^{0}$ + 5. $1^{4}$ $(2x)^{1}$ + 10. $1^{3}$ $(2x)^{2}$ + 10. $1^{2}$ $(2x)^{3}$ + 5. $1^{1}$ $(2x)^{4}$ + 1. $1^{0}$ $(2x)^{5}$

= 1 + 10x + 40x² + 80x³ + 80 $x^{4}$ + 32 $x^{5}$

8 0

3 years ago

HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP

levacccp [35]

$f(x) = \sqrt[3]{2x - 1} \\f(14) = \sqrt[3]{2(14) - 1} \\f(14) = \sqrt[3]{28 - 1} \\f(14) = \sqrt[3]{27} \\f(14) = 3$

$f(x) = \sqrt[3]{2x - 1} \\f(-62) = \sqrt[3]{2(-62) - 1} \\f(-62) = \sqrt[3]{-124 - 1} \\f(-62) = \sqrt[3]{-125} \\f(-62) = -5$

$f(x) = \sqrt[3]{2x - 1} \\f(20) = \sqrt[3]{2(20) - 1} \\f(20) = \sqrt[3]{40 - 1} \\f(20) = \sqrt[3]{39}$

4 0

3 years ago

Does 8, 10, 6 form a right triangle

loris [4]

Answer:

Step-by-step explanation:

8, 10, 6

10 - 8 = 2

2 + 6 = 8

8 0

3 years ago

Choose whether the probability is mutually exclusive or not

Semmy [17]

9514 1404 393

Answer:

mutually exclusive

Step-by-step explanation:

The formula of interest is ...

P(A or B) = P(A) + P(B) - P(A and B)

Filling in the given values, we have ...

9/10 = 2/5 + 1/2 - P(A and B)

Solving for P(A and B), we get ...

P(A and B) = 2/5 +1/2 -9/10 = 4/10 +5/10 -9/10

P(A and B) = 0

Events are mutually exclusive when <em>they can never happen at the same time</em>. That is, P(A and B) = 0.

The events A and B are mutually exclusive.

4 0

2 years ago