Answer:
Distance between Montpelier and Columbia is 1020
Step-by-step explanation:
51 mi/hr average:
d = 51 t
60 mi/hr average:
d t = 60*(t-3)
Substitute (1) into (2)
51 t = 60*(t-3)
51 t = 60 t + 180
9 t = 180
t = 20
d = 51 t
= 51 (20)
= 1020
let see distance is 1020 lets check
51 t = 60 * (t-3)
51 (20)= 60* (20-3)
1020 = 60*17
1020 = 1020
Answer:
correct answer is J
Step-by-step explanation:
I am assuming this is a triangle.....P = a + b + c
P = 2a - 3 + 2a + 3a + 1....combine like terms
P = 7a - 2 <==
The solution will be where the graph crosses the x-axis.
When a graph crosses the x-axis, the value of the function is 0. Just look at your graph and look at the x-values where the graph crosses the x-axis.
