Answer:
The Solution set is (x,y){(2,5)}
Step-by-step explanation:
The given equation is:
6x+4y=32
-6x+4y=8
We will use the elimination method:
By this method we will eliminate the variable x.
6x+4y=32
-6x+4y=8
________
8y=40
Divide both the sides by 8
8y/8=40/8
y=5
Now substitute the value of y in equation 2:
-6x+4y=8
-6x+4(5)=8
-6x+20=8
Move the constant value to the R.H.S
-6x=8-20
-6x= -12
Divide both the terms by -6
-6x/-6 = -12/-6
x= 2
The Solution set is (x,y){(2,5)}....
The gcf of 86,129 and 215 is <u>43</u>.
Answer:
x^2 - 5x - 66
Step-by-step explanation:
1. Distrubute the x to the x and -11 so you will get x^2 - 11x
2. Distrubute the 6 to x and -11 and you get 6x - 66
3. Combine like terms (x^2 - 11x + 6x - 66) you will get x^2 - 5x - 66
4 - (-12) = 16
difference = 16 degrees celcius.
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solution:
I choose 5 women from a pool of 10 in 10C2 ways.
I choose 5 men from a pool of 12 in 12C2 ways.
So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.
But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!
So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.
