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sp2606 [1]
3 years ago
13

If anyone knows this please help me. Please answer only if you know. Thanks! more points for you if answered!

Mathematics
1 answer:
Sauron [17]3 years ago
3 0
1a) Possible rational roots will be of the form
  ±{divisor of 10}/{divisor of 4}
Divisors of 10 are {1, 2, 5, 10}
Divisors of 4 are {1, 2, 4}

Then possible rational roots are
  {±1/4, ±1/2, ±1, ±5/4, ±2, ±5/2, ±5, ±10}

1b) Your answer is correct.

2) One additional root will be the conjuate of the given complex root.
  5 -3i

3) If one root is 5 -√7, another will be 5 +√7. Then your polynomial is
  P(x) = (x -(5 -√7))*(x -(5 +√7)) = (x -5)^2 -(√7)^2
  P(x) = x^2 -10x +18
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m=\frac{-3}{4}

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m=\frac{-4-(-1)}{5-1}

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Please help. Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact valu
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Area = (18 + 4.5π) cm²

Perimeter = (6√2 + 12 + 3π) cm

Step-by-step explanation:

The shaded region given is made up of triangle ABC and a semicircle

AB = BC = 6 cm (note that the triangle is a portion of a square)

Diameter of semi-circle (d) = BC = 6cm

Radius (r) = ½*6 = 3 cm

==>Area of the shaded region in terms of π

Area of shaded region = area of triangle + area of semicircle

Area = ½*a*b + ½*πr²

Area = ½*6*6 + ½*π3²

Area = 18 + ½*π9

Area = 18 + 4.5π

<em>Area of the shaded portion = (18 + 4.5π) cm²</em>

==>Perimeter of shaded region in terms of π

Perimeter of shaded region = perimeter of triangle + perimeter of semicircle

= Sum of all sides of the triangle + ½πd

Sides of triangles are AB = 6 cm, BC = 6 cm

Use Pythagorean theorem to find side AC:

AC² = AB² + BC²

AC² = 6² + 6² = 36 + 36 = 72

AC = √72 cm

Perimeter of shaded triangle = √72 + 6 + 6 = √72 + 12 = (6√2 + 12) cm

Perimeter of semicircle = ½*πd = ½π6

= 3π

<em>Perimeter of the whole shaded region in terms of π = (6√2 + 12 + 3π) cm</em>

<em></em>

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