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Arturiano [62]
3 years ago
8

(4a^3-3a-8) - (a-5) ​

Mathematics
2 answers:
arlik [135]3 years ago
8 0

Answer:

(

4

3

−

3

−

8

)

−

1

(

−

5

)

(4a^{3}-3a-8){\color{#c92786}{-1(a-5)}}

(4a3−3a−8)−1(a−5)

(

4

3

−

3

−

8

)

−

+

5

Step-by-step explanation:

PSYCHO15rus [73]3 years ago
7 0

Answer:

4a^{3} - 4a - 3

Step-by-step explanation:

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Help please. Im confused
sergij07 [2.7K]

Answer:

5x- 9 is your expression

Step-by-step explanation:

Decreased means subtraction and the product of any two numbers is multiplication.

Division Keyword: Divided by, or Quotient of.

Multiplication Keyword: Product of, or Multiplied by.

Subtraction Keyword: Subtracted from, or Decreased by.

Addition Keyword: Added to, or Increased by.

If there is no Variable then place the common Variables: X, Y, Z.

8 0
3 years ago
Read 2 more answers
9/10 times a number plus 6 is 51
goldenfox [79]
9/10n + 6 = 51
9/10n = 51 - 6
9/10n = 45
n = 45 * 10/9
n = 450/9
n = 50
5 0
3 years ago
Read 2 more answers
Write this number in expanded form 683,422
tekilochka [14]

Answer: 600,000+80,000+3,000+400+20+2

Step-by-step explanation:

Mark me as brainliest if this helps!

7 0
3 years ago
01.01) Rewrite the expression with rational exponents as a radical expression. 7 times x to the two thirds power cube root of th
jeka94

Answer:

(7x)^{\frac{2}{3} = (\sqrt[3]{7x})^2

Step-by-step explanation:

Given the expression (7x)^{\frac{2}{3}, to express this as a radical expressions, we'd apply the rule/law of indices that deals with converting expressions that has rational exponents into radical expressions.

The rule of indices to apply is: b^{\frac{m}{n}} = (\sqrt[n]{b})^m

To apply this to the expression, (7x)^{\frac{2}{3}, the denominator of the fraction of the exponent would determine the root, that is, cube root in this case. The numerator of the exponent would then determine the exponent of the radical expressions.

Thus:

(7x)^{\frac{2}{3} = (\sqrt[3]{7x})^2

6 0
3 years ago
Find the difference: (6y3 17y − 3) − (4y3 − 11y 9)
Natali [406]
If you would like to find the difference (6y^3 + 17y - 3) - (4y^3 - 11y + 9), you can do this using the following steps:

(6y^3 + 17y - 3) - (4y^3 - 11y + 9) = 6y^3 + 17y - 3 - 4y^3 + 11y - 9 = 2y^3 + 28y - 12

The correct result would be 2y^3 + 28y - 12.
8 0
3 years ago
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