Answer:
- time = 1second
- maximum height = 16m
Step-by-step explanation:
Given the height of a pumpkin t seconds after it is launched from a catapult modelled by the equation
f(t)=-16t²+32t... (1)
The pumpkin reaches its maximum height when the velocity is zero.
Velocity = {d(f(x)}/dt = -32t+32
Since v = 0m/s (at maximum height)
-32t+32 = 0
-32t = -32
t = -32/-32
t = 1sec
The pumpkin reaches its maximum height after 1second.
Maximum height of the pumpkin is gotten by substituting t = 1sec into equation (1)
f(1) = -16(1)²+32(1)
f(1) = -16+32
f(1) = 16m
The maximum height of the pumpkin is 16m
Answer: approximately 29 feet
Explanation: You need to find a tree so that the angle of elevation from the end of the shadow to top of the tree is 40 degrees.
The length of the shadow is an adjacent side and is 35.
The height of the tree is the opposite side. You could use X.
Tan ratio = opposite/adjacent
tan(40) = x/35
x = 35*tan(40) =29.37
Answer:
The expression that can be used to calculate the rate per second at which the machine launches the balls is fraction 20 over 4.
Step-by-step explanation:
The x-axis label is Time in seconds, and the x-axis values are from 0 to 20 in increments of 4 for each grid line.
And the y-axis label is Number of Balls and the y-axis values from 0 to 100 in increments of 20 for each grid line.
If the ordered pairs (4,20) and (8,40) are on the graph, then the slope of the line will be represented by
Therefore, the expression that can be used to calculate the rate per second at which the machine launches the balls is fraction 20 over 4. (Answer)
Answer:
w + 2.3 > 18
Step-by-step explanation:
w + 2.3 is the representation of a number w added to 2.3. We also know that this is more than (>) 18. Overall this can be represented by:
w + 2.3 > 18
