Ok so there are 52 cards in a deck if you take all the cards that have the number 6 which is only 4 cards so 52-4 = 48 cards without any 6 so the ratio is 48/52
chances.
If you're trying to take any card that is greater than 6 its a little more complex there is T,2,3,4,5,6,7,8,9,10,B,Q,K so you have to tack away 6,7,8,9,10,B,Q,K from 4 rows so 8 x 4 =32 cards 52-32= 20 so the probability of not having any cards greater than 6 is 20/52
There are two ways to work this out: normal variables or using "imaginary" numbers.
Normal variables:
![(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}](https://tex.z-dn.net/?f=%20%287%2B2i%29%283-i%29%5C%5C%287%2A3%29%2B%5B7%2A%28-i%29%5D%2B%283%2A2i%29%2B%5B2i%2A%28-i%29%5D%5C%5C21-7i%2B6i-2i%5E%7B2%7D%5C%5C%5C%5C21-i-2i%5E%7B2%7D)
Imaginary numbers:
Using the result from earlier:

Now since

, then the expression becomes:
Answer:
78º
Step-by-step explanation:
<u>Note</u> : -
In mathematics, the reference angle is defined as the acute angle and it is measuring less than 90 degrees. It is always the smallest angle, and it makes the terminal side of an angle with the
x - axis.
<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>1</u> : -
Find where 192º lies in which quadrant.
192º lies in 3rd quadrant ( between
180º and 270º )
<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>2</u> : -
Subtract : 270 - 192
270 - 192 = 78º
( Since, 192º is greater than 180º, is subtracted from 270º )
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u> : -
78º is the reference angle for 192º.
Answer:
Step-by-step explanation:
1. 2x - 28
2. 6x3 - 4x2 + 2x
3. x2 + 7x + 12
4. m2 - 4mn + 21n2
5. x2 - 9x + 18
Answer:
b
Step-by-step explanation:
x = 2 in this situation, so plug in 2 for x.
f(2) = (x + 1)2
f(2) = (2 + 1)2
f(2) = (3)2
f(2) = 6
f(2) = 6. That means b is the answer.