Question

Find three consecutive integers for which 3 times the sum of the first and third integers is -342.

Answer 1

Answer:

             -58, -57, -56

Step-by-step explanation:

x       - the first of consecutive integers

x+1   - the second of consecutive integers

x+2  - the third of consecutive integers

x+x+2  - sum of the first and third integers

3(x+x+2)  - three times the sum of the first and third integers

3(x+x+2) = -342

  ÷3             ÷3

2x + 2 = -114

  -2            -2

 2x = -116

 ÷2     ÷2

   x = -58

x+1 = -58 + 1 = -57

x+2 = -58 + 2 = -56