Answer:
1) f
4 * ¼ = 1 (Multiplicative inverse property)
2) c
6 * 1 = 6 (Identity property of multiplication)
3) h
5 + 7 = 7 + 5 (Commutative property of addition)
4) j
If 5 + 1 = 6 and 4 + 2 = 6, then 5 + 1 = 4 + 2 (Transitive property)
5) a
4(x - 3) = 4x - 12 (Distributive property)
6) i
3(5) = 5(3) (Commutative property of multiplication)
7) k
Rules that allow us to take short cuts when solving algebraic problems.(Properties)
8) d
5 * (3 * 2) = (5 * 3) * 2 (Associative property of multiplication)
9) g
4 + (-4) = 0 (Additive inverse property)
10) e
2 + 0 = 2 (Identity property of addition)
11) b
A + (B + C) = (A + B) + C (Associative property of addition)
Answer:
10.9=n
Step-by-step explanation:
Answer:
it should be the negative repirocal of -2 so 1/2
Answer:http://avconline.avc.edu/jdisbrow/ma115/Practice%20Test%203%20with%20answers.pdf
Step-by-step explanation:
you welcome
The real solutions of f(x) = 0 is; x = -8, 0 and 4
<h3>How to find the roots of a polynomial graph?</h3>
When talking about real solutions of a polynomial, we are simply referring to the values of x that make the polynomial f(x) = 0.
Now, in a polynomial graph as attached, the real solutions are the roots and they are the values of x where the curve crosses the x-axis.
From the given graph, the real solutions are at x = -8, 0 and 4
Thus, we conclude that the real solutions of f(x) = 0 is; x = -8, 0 and 4
Read more about Polynomial roots graph at; brainly.com/question/14625910
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