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3 years ago

4/-2 flipped over the x axis

Mathematics

1 answer:

AleksandrR [38]3 years ago

3 0

Answer:

I suppose that here we have:

"(4, - 2) flipped over the x-axis"

Regardless of that, i will answer this in a kind of general way.

When we have a point (x, y) and we do a reflection over the x-axis (or the line y = 0, is the same) the reflected point will be (x, - y)

If we instead had a reflection over the y-axis (or the line x = 0) the reflected point will be (-x, y)

Then if we have the point (4, -2) and we have a reflection over the x-axis, the sign of the y-component needs to change.

Then the reflected point will be (4, -(-2)) = (4, 2)

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A line with slope $\frac 23$ contains the point $P(-18, -12)$. What is the $x$-intercept of the line?

Vadim26 [7]

Answer: Therefore, the x-intercept of the line is 0

A line with slope 2/3 contains the point P(-18, -12). What is the x intercept of the line?

Step-by-step explanation:

Given;

Slope m = 2/3

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3 years ago

Please help me

madreJ [45]

Answer:

1) The total displacement vector is ((16 + √2)/2, -(6+11·√2)/2)

2) The number of miles they'd have to walk is approximately 13.856 miles

Step-by-step explanation:

1) The distance, direction, and location of the path of the walk the person takes, are listed as follows;

Start location, (0, 0)

6 miles East walk to location, (6, 0)

6 miles Southeast to location, (6 + 3·√2, -3·√2)

3 miles South to location, (6 + 3·√2, -3·√2 - 3)

5 miles Southwest to location, (6 + 3·√2 - 2.5·√2, -3·√2 - 3 - 2.5·√2)

2 miles East to location, (6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2)

(6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2) = ((16 + √2)/2, -(6+11·√2)/2)

Therefore the destination coordinates is ((16 + √2)/2, -(6+11·√2)/2)

The total displacement vector, $\underset{d}{\rightarrow}$ = ((16 + √2)/2, -(6+11·√2)/2)

d = (16 + √2)/2)·i - (6+11·√2)/2)·j

2) If the person walked straight home, the number of miles they'd have to walk, $\left | \underset{d}{\rightarrow} \right |$ , is given as follows;

$\left | \underset{d}{\rightarrow} \right | = \sqrt{\left(\dfrac{16 +\sqrt{2} }{2} \right)^2 + \left(-\dfrac{6 + 11 \cdot \sqrt{2} }{2} \right)^2 } = \sqrt{134 + 41 \cdot \sqrt{2} }$

Therefore;

If the person walked straight home, the number of miles they'd have to walk $\left | \underset{d}{\rightarrow} \right | \approx 13.856 \ miles$

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