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2 years ago

What is the sum of two consecutive integers that equal 131

Mathematics

1 answer:

QveST [7]2 years ago

8 0

The answer would be 65 and 66
65+66 = 131

a + (a + 1) = 131
- 1 -1
2a = 130
/2 /2
a = 65
a + 1= 66

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Answer:

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Step-by-step explanation:

Here, the given expression is $15x^{2} = 4x -1$

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Now the discriminant (D) of a quadratic equation $ax^{2} +b x + c = 0$

D = $b^{2} - 4ac = (-4)^{2} - 4(15) (1) = 16 - (60) = -44$

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As D< 0, so the roots will be imaginary.

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So, here $x = \frac{-(-4) \pm \sqrt{D} }{2a} = \frac{4 \pm \sqrt{(-44 )} }{30}$

So, either $x = \frac{4 + \sqrt{(-44 )} }{30} or, x = \frac{4 - \sqrt{(-44 )} }{30}$

or, $x = \frac{2 +\sqrt{11} i}{15} or, x = \frac{2 - \sqrt{11} i}{15}$

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