3 years ago

What is the sum of two consecutive integers that equal 131

1 answer:

QveST [7]3 years ago

8 0

The answer would be 65 and 66
65+66 = 131

a + (a + 1) = 131
- 1 -1
2a = 130
/2 /2
a = 65
a + 1= 66

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Crazy boy [7]

Answer: Solution: $a=\dfrac{-19}{3}$ and $b=\dfrac{1}{3}$ .

Step-by-step explanation:

The given pair of equations:

$a-8b= -9\ ...(i)\\\\ a-2b= -7\ ...(ii)$

Eliminate equation (i) from (ii) , we get

$-2b-(-8b)=-7-(-9)\\\\\Rightarrow\ -2b+8b=-7+9\\\\\Rightarrow\ 6b=2\\\\\Rightarrow\ b=\dfrac{1}{3}$

Put value of b in (ii) , we get

$a-2\times\dfrac{1}{3}=-7\\\\\Rightarrow\ a=-7+\dfrac{2}{3}\\\\\Rightarrow\ a=\dfrac{-21+2}{3}\\\\\Rightarrow\ a=\dfrac{-19}{3}$

Solution: $a=\dfrac{-19}{3}$ and $b=\dfrac{1}{3}$ .

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solmaris [256]

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RSB [31]

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Zarrin [17]

I think it would be 88

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3 years ago

Scilla [17]

Answer:

2(2y+9)

Step-by-step explanation:

6y+10-2y+8

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hope it helps.

just sitting here waiting for brainliest.

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