Selecting 5 students to participate in a math contest would require combinations.
<u>SOLUTION:
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given that, Selecting 5 students to participate in a math contest would require the calculating of a permutation or combination?
So, we need to differentiate between permutations and combinations.
Permutations - In mathematics, permutation is the act of arranging the members of a set into a sequence or order
Combinations - In mathematics, a combination is a selection of items from a collection, such that the order of selection does not matter.
So, now, for our math test, we just require students but not in an order nor with arrangements.
Hence, selecting 5 students to participate in a math contest would require combinations.
Hey there! :)
Answer:
1124.8 J.
Step-by-step explanation:
Given:
Distance: 25 meters.
Force: 70 N.
Direction: 50° with the horizontal.
Start by calculating the magnitude of the vector:
cos (50) = |x| / 70
70 · cos (50) = |x|
Solve:
44.99 ≈ |x|
This is the magnitude. To calculate the amount of work done, simply multiply by the distance she pushed the wheelbarrow:
44.99 × 25 ≈ 1124.8 J.
Answer:
799 x 10^6
Hope this helps
Regularly it would be 799 x 1,000,000 so I converted it.
Answer:
5/3
Step-by-step explanation:
Set it up like multiplying fractions
5/18 * 6/1
Then you can simplify this by turning the numerator 6 into a 1 and the denominator 18 into 3.
5/3 * 1/1
5/3 times 1 equals to 5/3.
By <span>(x + 5/x^2 + 9x + 20) you apparently meant the following:
x+5
----------------------
x^2 + 9x + 20
and by
</span><span>(x^2-16/x-4)
x^2-16
you apparently meant ---------------
x - 4
Please use additional parentheses for clarity.
Dividing,
</span> x+5 (x-4)(x+4)
---------------------- * ---------------
x^2 + 9x + 20 x-4
Now, x^2 + 9x + 20 factors into (x+4)(x+5), so what we have now is
(x+5)(x+4)
------------------------- = 1 This is true for all x, so there are no exclusions.
(x+4)(x+5)
