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viva [34]
3 years ago
7

Shelby's Ice Cream Shop sold 8 sundaes with nuts and 4 sundaes without nuts. What is the ratio of the number of sundaes with nut

s to the number of sundaes without nuts?
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
3 0

Answer: 2:1

Step-by-step explanation:

The ratio of A to B is given by :  \dfrac{A}{B} or A : B  .

Given : sundaes with nuts  = 4

sundaes without nuts = 8

The ratio of the number of sundaes with nuts to the number of sundaes without nuts = \dfrac{8}{4}=\dfrac{2}{1}\ \ \ [\text{Divide numerator and denominator by 4 }]

= 2:1

hence, the required ratio = 2:1 .

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The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

8 \times h + 5 \times f = 24

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

6 \times h + 2 \times f = 16.60

6h + 2f = 16.60 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

<h3>h = 2.5</h3>

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

<h3>f = 0.8</h3>

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

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