Answer:
A
Step-by-step explanation:
Answer:
y" = -24 / y³
Step-by-step explanation:
6x² + y² = 4
Take the derivative of both sides with respect to x.
12x + 2y y' = 0
Again, take the derivative of both sides with respect to x.
12 + 2y y" + y' (2y') = 0
12 + 2y y" + 2(y')² = 0
Solve for y' in the first equation.
2y y' = -12x
y' = -6x/y
Substitute and solve for y":
12 + 2y y" + 2(-6x/y)² = 0
12 + 2y y" + 2(36x²/y²) = 0
12 + 2y y" + 72x²/y² = 0
6y² + y³ y" + 36x² = 0
y³ y" = -36x² − 6y²
y" = (-36x² − 6y²) / y³
Solve for y² in the original equation and substitute:
y² = 4 − 6x²
y" = (-36x² − 6(4 − 6x²)) / y³
y" = (-36x² − 24 + 36x²) / y³
y" = -24 / y³
Answer:
a) There are 9 outcomes.
b) **i have attached the tree diagram**
c) 1/9
d) 1/9
Step-by-step explanation:
Both events (choosing a shirt and choosing pants) are not mutually exclusive (disjoint). Meaning that both events can occur at the same time.
a) For a sequence of two events in which the first event can occur <em>m</em> ways and the second event can occur <em>n</em> ways, the events together can occur a total of <em>m</em> • <em>n</em> ways. So for this problem, you would do 3 • 3 which equals 9.
b) **tree diagram is attached**
c) Because there are two different events occurring (choosing a shirt and choosing pants) you need to multiply using the Multiplication Rule for Independent Events : P(A and B) = P(A) * P(B)
The probability of event A occurring (choosing a red shirt) is 1/3 and the probability of event B occurring (choosing brown pants) is also 1/3.
1/3 * 1/3 = 1/9
d) You would do the same thing here as part c.
The probability of event A occurring (choosing a blue shirt) is 1/3 and the probability of event B occurring (choosing blue pants) is again 1/3.
1/3 * 1/3 = 1/9
I hope this was helpful!! :)
Step-by-step explanation:
okay I think you can solve this question
Answer:
B) 105.20
Step-by-step explanation:
491.60 + 157.68 - 68.44 = 581.20