2l + 2w = 16
2(l + w) = 16
l + w = 8
Lengths could be any numbers greater than 0 and less than 8
0 < l < 8
Answer:
-1 < x < 4.
Step-by-step explanation:
- 6 < 2x - 4 <4
2x - 4 < 4
2x < 8
x < 4. Also we have:
2x - 4 > -6
2x > -2
x > -1.
Answer:
C. 16x+9=4x
Step-by-step explanation:
Simplify 1/3(6x - 15) to 6x - 15/3
6x - 15/3 = 1/2(10x - 4)
Factor out the common term; 3
3(2x - 5)/3 = 1/2(10x - 4)
Cancel out 3
2x - 5 = 1/2(10x - 4)
Simplify 1/2(10x - 4) to 10x - 4/2
2x - 5 = 10x - 4/2
Factor out the common term; 2
2x - 5 = 2(5x - 2)/2
Cancel out 2
2x - 5 = 5x - 2
Subtract 2x from both sides
-5 = 5x - 2 - 2x
Simplify 5x - 2 - 2x to 3x - 2
-5 = 3x - 2
Add 2 to both sides
-5 + 2 = 3x
Simplify -5 + 2 to -3
-3 = 3x
Divide both sides by 3
- 1 = x
Switch sides
<u>x = -1</u>
Answer:
C. 4,100
Step-by-step explanation:
"60% more" is represented by a multiplier of 1 + 0.60 = 1.60.
"60% fewer" is represented by a multiplier of 1 - 0.60 = 0.40.
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Let b represent the number of booklets distributed by Team B. Then the number distributed by Team A is ...
1.60 × (0.40b) . . . . 60% more boxes, each with 60% fewer booklets
= 0.64b
Then the total distributed by both teams is ...
b + 0.64b = 1.64b = (164/100)b = (41/25)b
The only answer choice that is a multiple of 41 is ...
4,100 . . . choice C
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For 4100 to be the number of booklets distributed by both teams, Team B will have distributed 2500 booklets, and Team A will have distributed 1600 booklets. Team A might have distributed 160 boxes of 100 booklets, while Team B might have distributed 100 boxes of 250 booklets.