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My name is Ann [436]
3 years ago
13

melinda has a map of her city. the map uses a scale of 1 inch = 8 mile. Melinda's house is 1 1/2 inches away from the library on

the map. how far apart would her house and the library be on the map if the scale were 1 inch = 6 mile?
Mathematics
1 answer:
BigorU [14]3 years ago
3 0

Answer:

2 inches

Step-by-step explanation:

her house is 12 miles away from the library so if its 1 inch per 6 mile

then multiply both by 2 to get 2 inches for 12 miles

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PLEASE HELP ASAP!!
saul85 [17]

Answer:

slope 1.5, passes through (0, 5) 62/87,21 Substitute m = 1.5 and ( x, y) = (0, 5) in the equation y

Step-by-step explanation:

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8 0
3 years ago
Ed plants trees in city parks. He used 1\10 of a bag of fertilizer around the base of a newly planted tree. How many trees can E
valina [46]
To determine this you could think of it in a couple ways.

1. If it takes 1/10 of a bag of fertilizer to put around 1 tree, he can fertilize 10 trees with 1 bag because there are 10 groups of 1/10 in a bag. Take 10 x 40 because there are 40 bags and get 400 trees to be fertilized.

2. You can divide 40 by 1/10 as the other strategy.
This is the same as 40 x 10/1.

Also equaling 400 trees that can be fertilized.
4 0
2 years ago
14. BUS TRIP A bus leaves at 10 A.M. to take students on a field trip to a
k0ka [10]

The bus is 54.5 miles far from the site at the time of 11:30A.M as per the given information in the question.

<h3>What is the slope of a line?</h3>

The slope of a line indicates how steep it is. Slope is defined mathematically as "climb over run" (change in y divided by change in x).

It is assumed that a bus moving at a constant speed departs at 10 a.m. towards a historic location, is 100 miles away by 10:25 a.m., and is 65 miles away at 11:15 a.m.

We must create a point-slope equation that connects the distance from the place to the time in minutes after 10:00 a.m. Then, around 11:30 a.m., we need to figure out how far the bus is from the site.

A line's point-slope is y₂-y₁)=m(x₂-x₁)

Since x denotes the amount of minutes after 10:00 a.m., 10:25 a.m. is represented by x=25 and 11:15 a.m. by x=75.

At 10:25 a.m., a distance of 100 miles from the place is represented by 75.

The point represents a distance of 100 miles from the site at 10:25 a.m. The point represents a distance of 65 miles from the site at 11:15 a.m.

By substituting the points (25, 100) and (75, 65) into the slope formula and simplifying we get,

m=(y₂-y₁)/(x₂-x₁)

m=(65-100)/(75-25)

m=-35/50

m=-0.7

Now choose one of the points and substitute that point and the slope into the slope-point form

y₋y₁=m(x-x₁)

By choosing (x₁, y₁)=(25, 100)

By choosing (x₂, y₂)=(75, 65)

Since 11:30 A,M is 90 minutes after 10:00A.M

By substituting x=90 in the equation we get the value of y,

y-100= -0.7(90-25)

y-100= -0.7(65)

y-100 =-45.5

y= 54.5

Hence, the bus is 54.5 miles from the site at the time of 11:30 A.M

y-100= -0.7(x-25)

OR

y-65= -0.7(x-75)

The bus is 54.5 miles from the site at 11:30A.M.

To know more about slope of a line, visit:

brainly.com/question/28771374

#SPJ9

6 0
1 year ago
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