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3 years ago

Please help asap i dont understand at all

Mathematics

2 answers:

RideAnS [48]3 years ago

8 0

Answer:

Reflect shape A over the y-axis and vertically translate shape A downward 1 unit.

OleMash [197]3 years ago

8 0

Flip to the Right, And Down 1 Time.

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Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

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3 years ago

A certain brand of coffee comes in two sizes. A 12.3-ounce package costs $2.99 . A 33.9-ounce package costs $8.74 . Find the uni

aalyn [17]

Answer:

$12.3 - 33.9 = 21.6 \div 10 = 2.16$

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2 years ago

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Rudiy27

Answer:

$\overline{\text{BC}}=\boxed{22}$

Step-by-step explanation:

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2x -24 = x -2

x = 22 . . . . . . . . . add 24-x

The length of BC is x, so is 22.

BC = 22

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3 years ago

Apply a 90 degree rotation to the point (1, 2)

Makovka662 [10]

Hmm I use to know this wait a second I’ll answer it

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UNO [17]

Answer: Soliciting help from outside sources is a violation of your school's Honor Code and academic integrity agreement.

Step-by-step explanation:

Do your best and work with your teacher to ensure that you understand the requirements of this project and are prepared to submit great work!

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