The range of the function f(x) = |x| is [0,∞)
<h3>How to determine the range?</h3>
The function is given as:
f(x) = |x|
The above is the parent equation of an absolute value function.
The above function cannot output any negative value.
This means that:
ƒ(x) >= 0
As an interval notation, we have:
[0,∞)
Hence, the range of the function f(x) = |x| is [0,∞)
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Answer:
x = 9.5
Step-by-step explanation:
Y-intercept happens at x=0. Plug that into the equation. you'll get the y-intercept happens at (0,6). Then, to find the x-intercept y=0. Plug that into the equation. You'ff find that the x-intercept happens at (-9,0)
Hello :
625^1/4=((625)^1/2)^1/2 =√(√625) = √25 =5 because : √625 = 25
Assuming that c is the length of AB (as is usually the case in the angle-side notation for triangles):
If sin(35) = 12/c, we can transform by multiplying both sides by c, and dividing both by sin(35) to get
c = 12/sin(35)
Evaluating using a calculator gives 20.92 units.
