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3 years ago

Which if the following lines has a slope of -1/2? A). x+2y=0 B). x-2y=0 C). -x+2y=0

Mathematics

1 answer:

NikAS [45]3 years ago

5 0

Answer:

A) x + 2y = 0

Step-by-step explanation:

In solving for y, you would follow these steps:

Subtract x in order to get 2y = -x

Divide by 2 on both sides to get y = -1/2x

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(Algebra II) Extra points!!Determine whether y varies directly with x

ludmilkaskok [199]

Answer:

k = 1.6
y = 1.6x

Step-by-step explanation:

If the variation is proportional dividing the y-value by the x-value will give the same result for all table entries. That quotient is the constant of variation (k).

Here 6.4/4 = 11.2/7 = 16/10 = 20.8/13 = 1.6

The value of y varies directly as x, and the constant of variation is 1.6. The equation is ...

y = 1.6x

8 0

3 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

3 years ago

What is 6/9 written as a fraction?

babunello [35]

6\9 to the simplest fraction is 2\3

5 0

3 years ago

PLEASE HELP!!

Amanda [17]

Answer: You could move Circle 2 10 units to the right and up 5 up.

Doing this would put the centers of the circles at the same location. They would both be at the point (8, 5).

For the dilation, the radius changed from 2 to 6. Solve the following equation.
2x = 6
x = 3

7 0

3 years ago

Read 2 more answers

Consider the two functions described below. Function 1 describes the cost, y, to park in a parking lot for x hours. There is a f

Len [333]

Statement B explains correctly that the parking garage charges a higher rate per hour than the parking lot. Statements B and D are the same.

Step-by-step explanation:

Step 1:

For the parking lot, there is a flat fee of $7.00 and then a charge of $1.00 every hour.

So if a vehicle was parked for 1 hour charges are 7 + 1 (1) = $8,

If parked for two hours charges are 7 + 1 (2) = $9.

Step 2;

To understand the pricing of the parking garage, we must plot the points of the graph.

The points on the graph are (0, 4), (1, 6), (2, 8), (3, 10), (4, 12), (5, 14)...

So for the parking garage, there is a flat fee of $4 and then a charge of $2.00 every hour.

So if a vehicle was parked for 1 hour charges are 4 + 2 (1) = $6,

If parked for two hours charges are 4 + 2 (2) = $8.

Step 3:

Comparing both the parking lot and the parking garage, we get that the flat fee for the parking lot is higher while the parking charges for an hour are higher for the parking garage which is statement B.

Statement B and D are the same.

7 0

3 years ago