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coldgirl [10]
2 years ago
12

Help pls ty in advance

Mathematics
1 answer:
svetoff [14.1K]2 years ago
7 0

\bold{\huge{\underline{ Solution\: 2 }}}

  • The name of the circle is <u>IJKL</u>
  • The name of central Angle
  • \sf{\underline{= {\angle} IHJ }}
  • The name of the secant = <u>KL</u>

{\bigstar}Circle :- It is a round figures, which has no end points.

{\bigstar} Central angle :- It the angle ,which lie in the middle of the circle.

  • Here, H is the mid point of the circle .So, Angle IHJ is the central angle.

{\bigstar} Secant :- A line drawn in circle in such a way that it intersect the circle from two distinct points. Then, It is called secant .

  • Here, KL is the line which acts as a secant because it intersect the circle from point K and point L.

\bold{\huge{\underline{ Solution\: 3 }}}

  • Semicircle = FGH and FIH
  • Minor Arc :- FG or GH
  • Major Arc :- FHG or GFH

{\bigstar} Semicircle :- Semicircle is nothing but the half of the circle.

<u>Here</u><u>, </u><u>In </u><u>second </u><u>diagram </u>

  • FGH and FIH are acting as two semicircles which simulatineously forming one circle.

{\bigstar} Minor Arc :- Minor Arc is nothing but the smaller arc of the circle and it is always smaller than the half of the circle that is semicircle.

<u>Here</u><u>, </u>

  • FG or GH are the minor arc of the given circle.

{\bigstar} Major Arc :- Major Arc is nothing but the largest arc of the circle and it is always larger than the half of the circle that is semicircle.

<u>Here</u><u>, </u>

  • FHG or GFH is the major arc as it is larger than the semicircle of the given circle .
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Anyone for geometry #’s 5 &amp; 6
vesna_86 [32]

Answer:

5.   m < 1 = 72 degrees.

6.    m < 1 = 80 degrees.

Step-by-step explanation:

5. < 1 = 72 degrees.

If we draw a line through the point of < 1,  We see that  We have have 2 angles  of 40 and 32 ( alternate angles).

6.  By the same reasoning m < 1 = 60 + 20

= 80 degrees.

3 0
3 years ago
Which expression is equivalent to 9(9m+3t)
vitfil [10]

Answer:

81m + 27t

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
is a whole number with 4 digits always greater than or less than a whole number with 3 digits explain
Yuri [45]
Answer:
A whole number with 4 digits is always greater than a whole number with 3 digits.
This requires that both numbers be positive.

Explanation.
In the decimal system, we count 0,1,2, ..., 9 (1st digit).
When we reach 10, we shift left and count in tens from 10,20,30, ..., 90 (2nd digit).
When we reach 100, we shift left and count in hundreds from 100,200,300, ..., 900 (3rd digit).
Then we count in thousands as 1000,2000, ...  ( 4th digit).

Because the 4th digit counts in thousands and the 3rd digit counts in hundreds, a whole number in the 4th digit will be greater than a whole number in the 3rd digit.
8 0
3 years ago
Verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial
Mariulka [41]

Answer:

i) Since P(2), P(-1) and P(½) gives 0, then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

ii) - the sum of the zeros and the corresponding coefficients are the same

-the Sum of the products of roots where 2 are taken at the same time is same as the corresponding coefficient.

-the product of the zeros of the polynomial is same as the corresponding coefficient

Step-by-step explanation:

We are given the cubic polynomial;

p(x) = 2x³ - 3x² - 3x + 2

For us to verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial, we will plug them into the equation and they must give a value of zero.

Thus;

P(2) = 2(2)³ - 3(2)² - 3(2) + 2 = 16 - 12 - 6 + 2 = 0

P(-1) = 2(-1)³ - 3(-1)² - 3(-1) + 2 = -2 - 3 + 3 + 2 = 0

P(½) = 2(½)³ - 3(½)² - 3(½) + 2 = ¼ - ¾ - 3/2 + 2 = -½ + ½ = 0

Since, P(2), P(-1) and P(½) gives 0,then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

Now, let's verify the relationship between the zeros and the coefficients.

Let the zeros be as follows;

α = 2

β = -1

γ = ½

The coefficients are;

a = 2

b = -3

c = -3

d = 2

So, the relationships are;

α + β + γ = -b/a

αβ + βγ + γα = c/a

αβγ = -d/a

Thus,

First relationship α + β + γ = -b/a gives;

2 - 1 + ½ = -(-3/2)

1½ = 3/2

3/2 = 3/2

LHS = RHS; So, the sum of the zeros and the coefficients are the same

For the second relationship, αβ + βγ + γα = c/a it gives;

2(-1) + (-1)(½) + (½)(2) = -3/2

-2 - 1½ + 1 = -3/2

-1½ - 1½ = -3/2

-3/2 = - 3/2

LHS = RHS, so the Sum of the products of roots where 2 are taken at the same time is same as the coefficient

For the third relationship, αβγ = -d/a gives;

2 * -1 * ½ = -2/2

-1 = - 1

LHS = RHS, so the product of the zeros(roots) is same as the corresponding coefficient

7 0
3 years ago
Find the solution of the system of equations.<br> 10x+10y=40 <br> 5x+3y=8
ddd [48]

Answer:

x = -2 & y = 6

Step-by-step explanation:

10x+10y=40

10x+10y+ -10y=40+-10y

10x=-10y+40

\frac{10x}{10} =\frac{-10y+40}{10}

x=-y+4

5x+3y=8

5(-y+4)+3y=8

-2y+20=8

-2y+20+-20=8+-20

-2y=-12

\div2

y=6

x=-y+4

x=-6+4

x=-2

Hope this helps.

7 0
2 years ago
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