The answer is 1. A<span>lcoholic Fermentation
Hope that helped :)</span>
Answer:
import java.util.Scanner;
import java.lang.*;
class Main
{
public static void main(String args[])
{
int n;
//For capturing the value of n
Scanner scanner = new Scanner(System.in);
System.out.println("Enter the value of n:");
//The entered value is stored in the var n
n = scanner.nextInt();
int k=1;
printnum(n,k);
}
public static void printnum(int n,int k)
{
if(n%2==0)
{
for(int i=k;i<=n-1;i=i+2)
{
System.out.print(i);
}
System.out.println("");
}
else
{
for(int i=k;i<=n-1;i=i+2)
{
System.out.print(i);
}
System.out.println("");
}
n--;
if(n<=1)
{
System.exit(0);
}
else
{
printnum(n,k+1);
}
}
}
Explanation:
The program is self explanatory.
def dx(fn, x, delta=0.001):
return (fn(x+delta) - fn(x))/delta
def solve(fn, value, x=0.5, maxtries=1000, maxerr=0.00001):
for tries in xrange(maxtries):
err = fn(x) - value
if abs(err) < maxerr:
return x
slope = dx(fn, x)
x -= err/slope
raise ValueError('no solution found')
Answer:
insert, illustrations, click and drag, slide show
Explanation:
i got it right
Answer: Parameters
Explanation:
Whenever a call to a recursive function is made, then the function has its own code and its own set of parameters with local variables. These parameters are within the scope of the recursive function. For example while finding the factorial of a number we are given the function with parameter such as int recursive(int n) where int n is a parameter passed into the function.