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Gekata [30.6K]
3 years ago
11

Print "Censored' if userlnput contains the word "darn, else print userlnput. End with newline. Ex: If userinput is "That darn ca

t., then output is: Censored Ex: If userlnput is "Dang, that was scary!", then output is: Dang, that was scary! Note: If the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report Program end never reached. The system doesn't print the test case that caused the reported message. 1 import java.util.Scanner; 3 public class CensoredWords 4public static void main ( 1 test passed String args) Scanner scnr -new Scanner(System.in); String userInput; A tests passed userInput scnr.nextLine); 10 Your solution goes here 12 13 Run
Computers and Technology
1 answer:
sasho [114]3 years ago
6 0

Answer:

The code is given below in Java with appropriate comments

Explanation:

//Import the input.

import java.util.Scanner;

class CensoredWords

{

    //Define the main method.

    public static void main(String args[ ])

    {

         //Define the variables.

         String userInput="" ;          

         //Define the scanner object

         Scanner scobj = new Scanner(System.in);

          //Accept the userInput.

         System.out.print("Enter String: ");

         userInput=scobj.nextLine();

         //Check if the input contains darn.

         //Print censored.

         if(userInput.toUpperCase().indexOf("DARN") != -1)

         System.out.printf("Censored");

         //IF the input does not contains darn

         //Print userInput.

         else

System.out.printf(userInput)

         return;

}

}

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Answer:

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{

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