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Anton [14]
1 year ago
15

X+16=_19 use balancing method​

Mathematics
2 answers:
Igoryamba1 year ago
4 0

Answer:

Simplifying

x + 16 = -19

Step-by-step explanation:

Reorder the terms:

16 + x = -19

Solving

16 + x = -19

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.

16 + -16 + x = -19 + -16

Combine like terms: 16 + -16 = 0

0 + x = -19 + -16

x = -19 + -16

Combine like terms: -19 + -16 = -35

x = -35

Simplifying

x = -35

horrorfan [7]1 year ago
3 0

Step-by-step explanation:

jjzjznzijxmxnjxndksnndjxnz z

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Find the value of x.
Arlecino [84]

Answer:

<h2>20</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • equation
  • PEMDAS
<h3>tips and formulas:</h3>
  • a straight line contains 180°
<h3>let's solve:</h3>

according to the question

7x+x+20=180

=>8x+20=180

=>8x=160

therefore

x=20

7 0
2 years ago
Which figure shows a reflection of ​pre-image QRS​ over the line t?
Igoryamba

Answer:

A, because its reflecting off of the y axis

Step-by-step explanation:

I have proof links, and I took the test

4 0
3 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
Mark the statements that are true.
qaws [65]

Answer:

Hi there!

The correct choices are: A, B, C

Step-by-step explanation:

π in radians equals to 180°

A is correct because 180/3 = 60

C is correct because 180/4 = 45

7 0
3 years ago
Can someone explain the question to me?
Lelechka [254]
Whats the question that u need help with?


8 0
3 years ago
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